Solve for y in the following equation.
x=(x+1)(x+y)

x=(x+1)(x+y)

Step 1: Flip the equation.x2+xy+x+y=x

Step 2: Add -x to both sides.x2+xy+x+y+−x=x+−xx2+xy+y=0

Step 3: Add -x^2 to both sides.x2+xy+y+−x2=0+−x2xy+y=−x

2Step 4: Factor out variable y.y(x+1)=−x2

Step 5: Divide both sides by x+1.y(x+1)x+1=−x2x+1y=−x2x+1

So the answer is: y= -x^2/ x+1

☆We need to solve for y:
☆Here is the question you asked:
x=(x+1)(x+y)

☆Add -x to both sides:
x^2+xy+x+y+−x=x+−x
x^2+xy+y=0

☆Add -x^2 to both sides:
x2+xy+y+−x^2=0+−x^2
xy+y=−x^2

☆Factor out variable y:
y(x+1)/x+1=−x2/x+1

☆Your answer is:
y=−x2/x+1

☆I hope this helps!☆

8-2x+3x2=6 and six is your answer