What is the solution to the following system? 3x + 10y -12z = 40 x - 5y = 0 x- 4z = 0 a.) (8, 40, 32) b.) (10, 2, 3) c.) (20, 4, 5) d.) (40, 8, 10)

C.) (20, 4, 5)

Step-by-step explanation:

The given system is

From (2), we have

From (3)

Substitute the values of y and z in equation (1), we get

Then

and  

Hence, the solution of the given system is (20,4,5)