Given: lm ∥ kn , kl ∥ nm lp = h­1 = 5 cm, mq = h2 = 6 cm pklmn = 42 cm find: area of klmn

  Area = 630/11 cm² = 57 3/11 cm²

Step-by-step explanation:

  Area = (5 cm)(KN) = (6 cm)(KL)

  Perimeter = 2(KN +KL) = 42 cm

So, ...

  KN = 1.2·KL . . . . divide the area equation by 5 cm

  1.2·KL +KL = 21 cm . . . . . divide the perimeter equation by 2

  KL = (21 cm)/2.2 . . . . . . . divide by the coefficient of KL

Substituting for KL in the area equation, we have ...

  Area = (6 cm)(21 cm)/2.2 = 630/11 cm²

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length