And show all work 7.04 use mathematical induction to prove the statement is true for all positive integers n, or show why it is false. (4 points each.) 1. 4 ⋅ 6 + 5 ⋅ 7 + 6 ⋅ 8 + + 4n( 4n + 2) = quantity four times quantity four n plus one times quantity eight n plus seven divided all divided by six 2. 12 + 42 + 72 + + (3n - 2)2 = quantity n times quantity six n squared minus three n minus one all divided by two for the given statement pn, write the statements p1, pk, and pk+1. (2 points) 2 + 4 + 6 + . . + 2n = n(n+1)

1]
4*6+5*7+6*8++4n(4n+2)=4(4n+1)(8n+7)/6
If we choose n=1, then 4*6=24 but 4(4*1+1)(8*1+7)/6=50. This implies that the general trm for the pattern shown is wrong. It should have been (n+3)(n+5) and not 4n(4n+2).

2] 12+42+72++(3n-2)2=n(6n²-3n-1)/2
Let's set n=1, this means that 12=12.
But n(6n²-3n-1)/2
=1(6*1²-3*1-1)/2
=(6-3-1)/2
=2/2
=1
This shows that the general term is incorrect. It should have been (30n-18) which when simplified we get 6(5n-3). Even if we get to correct the left hand side the sequence will still not be equal to what's on the right given n=1.

3] 2+4+6++2n=n(n+1)
P(1):2=1(1+1)
P(m):2+4+6+..+2m=m(m+1)
P(m+1):2(k+1)=(k+1)(k+2)

X> -2 is the simplified version.