The yard space is large enough to have a pool that has a diameter of 27 feet. if yolanda wants to keep the pool in proportion to the model, what will be the depth of the pool? 4.5 feet 5 feet 6 feet 6.75 feet

The image of the problem was not found. as a way to  understand the problem, an example image is attached.let>   depth  of the real pool>   diameter of the real pool  > depth  of the model pool> diameter of the model pool  > proportionwe know thatp= (hr/dr)=(hm/dm)therefore(hr/dr)=(hm/dm)i  use cross products to find a hrhr*dm=hm*> hr=[hm*dr]/dm      we knowhm=2 ftdm=5 ftdr=27 fthr=[2*27]/ > hr=10.8 ft      the answer ishr=10.8 ft 

D.