Will mark as brainliest. multiply the polynomials (a^2 + 3a – 7) and (2a^2 – a + 4). simplify the answer. show your work.

Given expressions:

a^2 + 3a - 4 and 2a^2 - a + 5

  So:

                 (a^2 + 3a - 4) (2a^2 - a + 5)

                 = a^2 (2a^2 - a + 5) + 3a (2a^2 - a + 5) - 4 (2^a - a + 5)

   = 2a^4 - a^3 + 6a^3 + 5a^2 - 3a^2 + 15a - 8a^2 + 4a - 20

   Combine like terms:

                 2a^4 - a^3 + 6a^3 + 5a^2 - 3a^2 + 15a - 8a^2 + 4a - 20

   = 2a^4 - a^3 + 6a^3 + 5a^2 - 3a^2 - 8a^2 + 15a + 4a - 20

   = 2a^4 + 5a^3 - 6a^2 + 19a - 20

   The product of the given polynomials is:

   2a^4 + 5a^3 - 6a^2 + 19a - 20

Step-by-step explanation:

I did the assignment for my Algebra 2 class. I hope this helps!

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb