Write an equation for the line that passes through (5, 1) and (6, 3). show me how to do it!

This is the equation that in the end it needs to be y=mx+b mx~slope b~ intersecting on y

1. label then x1,y1 , x2,y2
(5, 1) (6, 3)
x1 y1 x2 y2

2. plug them in this formula
m= y2-y1

X2,x1
m= 3-1

6-5
m= 2
slope is 2
1

y= 2x+ b. ( to find b take one of the cordiants )
-using (5,1)
- 1= 2(5)+b
- 1=10+b (subtract 10 on both sides)
- -9 =b. ( now you have b )

y=2x -9

easier way maybe would be to put it in a chart to find slope x|y it goes 6|3 goes down 2 down one 5|1 rise. =y 2 - = 2. slope is 2. follow the run= x. 1. steps before to find b

7.666270253x10 raised to the 18th power