Amotor scooter travels 14 mi in the same that a bicycle covers 5 mi. if the rate of the scooter is 4mph more than twice the rate of the bicycle, find both rates

We observe that 14 is 4 more than twice 5.

The scooter's rate is 14 mph.
The bicycle's rate is 5 mph.

time = distance/rate
14/(2b +4) = 5/b . . . . . . let b represent the bicycle's speed in mi/h
14b = 10b +20 . . . . . . . .cross multiply
4b = 20 . . . . . . . . . . . . . subtract 10b
b = 5 . . . . . . . . . . . . . . . divide by 4. Same answer as above.

7.3

step-by-step explanation:

81+30=111180 minus 111=691/2×19=9.569÷9.5=7.263157895~7.3