Karen measured her height as 147 cm. karen’s actual height is 142 cm. what is the approximate percent error of karen’s measurement? tell me how you got it

To find the percentage error , we divide the difference of the readings by the correct reading and then multiply by 100.

Here the actual height of Karen is 142 cm

But the height measures was 147 cm.

The difference in the measures is 147-142= 5 cm

Now the error = 5 cm

So error percentage

=

= 3.5%

The approximate percent error of Karen’s measurement is 3.5%

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

idk

step-by-step explanation: