Afunction is represented by y = cos (2π/5)x - 1. determine the amplitude and period of the function. what is the equation of the midline? a) amplitude is 1; period is 5; y = 0 b) amplitude is 1; period is 2/5; y = 1 c) amplitude is 1; period is 5; y = −1 d) amplitude is 1; period is 2π; y = −1 ( explain how you get it)

Given that: y = cos(2pi/5)x -1

The general form of cos function is y = A cos(Bx+C) +D

So amplitude = A=1

Period = 2pi/B=2pi/(2pi/5)= 5

Phase shift = -C/B= 0

Vertical shift = D=-1

So the equation of the midline is y=-1

Sot he correct option is C.

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10