Carbon-14 has a half-life of approximately 5,730 years. this exponential decay can be modeled with the function n(t) = n0. if an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? round the answer to the nearest hundredth. atoms

The answer is It is 35.36This is of the form f=ir^t.  We are given that the half life is 5730 years so we can say:
1=2r^5730
1/2=r^5730 taking natural log of both sides
ln0.5=5730lnr
lnr=(ln0.5)/5730 raising e to the power of both sides
r=e^((ln0.5)/5730)
r≈0.999879
so we have:
f=200(0.999879)^14325