Arocket is launched vertically from the ground with an initial velocity of 64 ft/s (a) write a quadratic function, h(t), that shows the height, in feet, of the rocket t seconds after it was launched (b) graph h(t) on a coordinate plane (c) use your graph from part b to determine the rockets maximum height, the amount of time it took to reach its maximum height, and the amount of time it was in the air. ! will give brainiest!

x=-5t^2+19t

step-by-step explanation:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

what i would say the best answer is a. 40.5