The perimeter of an isosceles triangle is 14 cm. one of its sides is twice longer than another of its sides. find all sides of the triangle.

The sides of the triangle are:

2.8 cm, 5.6 cm,5.6 cm.

Step-by-step explanation:

The perimeter of an isosceles triangle is given=14 cm.

Now in an isosceles triangle the length of two sides are equal and the third side is unequal.

Now,it is given that:

One of its sides is twice longer than another of its sides.

As we know that in any triangle with sides lengths a,b and c  must hold that:

a<b+c and b<a+c and c<b+a

So, the equal sides are '2x 'and the unequal side is 'x'.

Hence, as we are  given the perimeter of the triangle that means:

x+2x+2x=14

5x=14

x=14/5=2.8 cm.

So, the sides of the triangle are:

2.8 cm, 5.6 cm,5.6 cm.

14/3 to7,14/3to7,0  to 7

Step-by-step explanation:

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option