The point (–1, 0.5) lies on the graph of f –1(x) = 2x. based on this information, which point lies on the graph of f(x) = log2x? (–0.5, 1) (0.5, –1) (1, –0.5) (1, 0.5)

(0.5, -1)
   f^-1(x) and f(x) are inverse functions of each other. That means that for all x, f^-1(f(x)) = x and f(f^-1(x)) = x. So for f^-1(x) we've been given the point (-1, 0.5) which means that we have an x value of -1 and a y value of 0.5. So if we swap the x and y values, we'll have a valid point for function f(x). Therefore an x value of 0.5 and a y value of -1 will work. So the answer is (0.5, -1). Notice that no math has to be done, you just need to know the meaning of inverse functions.