What is the completely factored form of the expression 16x2 + 8x + 32?

the given expression is

16 x² + 8 x + 32

= 8×2 x² + 8×1 + 8×4

= 8 × [ 2 x² + x +4]

finding the discriminant

d= b² - 4 a c

  = (1)² -4×2×4

  = 1 -32

  = -31< 0,

d< 0

so, the equation has no real root.so, the two imaginary roots are by using the formula of a quadratic equation→ ax² + bx +c=0

→

so ,16 x² + 8 x + 32= 8

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

what? ?

what type of question is thiss

step-by-step explanation: