The sum of three consecutive integers is 345. find the three integers.

Our three consecutive integers can be represented as

X ← first integer

X + 1 ← second integer

X + 2 ← third integer

Since the sum of our three consecutive integers is 345, our equation will read

X + X + 1 + X + 2 = 345

When we simplify on the left, our equation will now read

3x + 3 = 345

      -3      -3  ← subtract 3 on both sides

      3x = 342 ← divide both sides by 3

        X = 114

first integer = 114

second integer = 114 + 1 = 115

third integer = 114 + 2 = 116

Therefore, the three consecutive integers are 114, 115, and 116.

alot

step-by-step explanation:

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