Solve for x in the equation x^2-8x+41=0

I'm terrible at math any here is appreciated.

Find the zero function by factoring (try to show work) h(x)=-x^2-6x-9

Daryl factors the polynomial p(x)=x3+x2−26x+24 to rewrite it as p(x)=(x+6)(x−4)(x−1). which equations must be true? there may be more than one correct answer. select all correct answers. p(1)=0 p(−4)=0 p(−1)=0 p(6)=0 p(4)=0 p(−6)=0