Atotal of 8 classes, each with 20 students will go on the field trip. two chaperones are needed for each class. one bus will hold 25 people. write an expression

8 classes x 20 students per class = 160 students

8 classes x 2 chaperones per class = 16 chaperones

Total people on the buses . . . . . . . . . . 176 people

The expression for the number of buses needed is:

         Number of buses = 1 + (the greatest integer in 176/25)

That's because if there are any people left over after the
last full bus of 25, they will need one more bus.

Unfortunately for the school's budget, this group needs
7 full buses carrying 25 people in each, and one bus
carrying one single person in it.

A possible solution to the problem would be to find somebody
who is certified as a bus driver and willing to work two jobs
on the field trip, to act as one of the chaperones.  Then they
might get away with only 7 buses.

If this doesn't work, then they can just forget about the whole
idea of 25 on a bus.  Loading them to capacity doesn't help,
because it still leaves one person without a ride.  They might
as well just put one class and their chaperones on each of the
8 buses, and give each load a little bit of room to spread out.

If there's one student out of 160 who is sick or otherwise doesn't
show up on field-trip day, then they can squeeze everybody into
7 fully-loaded buses.  But since they had to reserve 8 buses and
drivers, they'll probably have to pay for the eighth one anyway.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.