Which numbers below belong to the solution set of the inequality 9x> 117

Given answer choices(?)
A.12
B.6
C.8
D.14
E.13
F. 19

117/9 equals 13, therefore we need numbers greater than 13 to multiply to 9 in order to get a number that is more than 117. Therefore x is numbers greater than 13. Choose all (if given the option) that is above number 13. Exclude all the numbers that are 13 and below. That means A, B, C, and E are not the correct answers nor possible solutions to the inequality. 

Bonus: I'll show you a hint on how you can figure out the products of 9 x 1 - 10. Take all ten of your fingers and hold down the number you want to multiply with 9. Let's say 4. Hold down your forth finger. The numbers before that finger is the tens and the fingers after is your ones. (Note that you don't count that finger that is down. The finger that is down (in this case your fourth) acts as a barrier between the tens and the ones values) Your answer would be 3 fingers in the front (meaning 3 tens) and 6 fingers in the back (meaning 6 ones) Together that's 36. 9 * 4 = 36.

(1/x + 1)^2 + 6 (1/x + 1) +5