Mathematics, 22.08.2019 00:30 CheerA170

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      (x² - y²)² + (2xy)² = (x² + y²)²
   (x² - y²)(x² - y²) + 2x²y² = (x² + y²)(x² + y²)
      x²(x² - y²) - y²(x² - y²) + 2x²y² = x²(x² + y²) + y²(x² + y²)
x²(x²) - x²(y²) - y²(x²) + y²(y²) + 2x²y² = x²(x²) + x²(y²) + y²(x²) + y²(y²)
      x⁴ - x²y² - x²y² + y⁴ + 2x²y² = x⁴ + x²y² + x²y² + y⁴
         x⁴ - 2x²y² + y⁴ + 2x²y² = x⁴ + 2x²y² + y⁴
   x⁴ - 2x²y² + 2x²y² + y⁴ = x⁴ + 2x²y² + y⁴
      x⁴ + y⁴ = x⁴ + 2x²y² + y⁴
      - x⁴    - x⁴
   y⁴ = 2x²y² + y⁴
       - y⁴ - y⁴
      0 = 2x²y²
      2    2
      0 = x²y²
      0 = xy

I didn't find the answer to the problem.

Answer from: Quest

step-by-step explanation:

; fx

Answer from: Quest

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

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