The resting heart rates for 80 women aged 46–55 in a simple random sample are normally distributed, with a mean of 71 beats per minute and a standard deviation of 6 beats per minute. assuming a 90% confidence level (90% confidence level = z-score of 1.645), what is the margin of error for the population mean? remember, the margin of error, me, can be determined using the formula mc014-1.jpg.

The margin of error is

Step-by-step explanation:

The margin of error represents the maximum expected difference between the true parameter and the estimated parameter.

Mathematically, it is calculated as,

where,

z = z score of the confidence interval,

σ = standard deviation,

n = sample size.

Putting the values,

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.