During a recent eruption, a piece of ash was ejected from a volcano with an initial velocity of 368 ft/sec. the height (h), in feet, of our ash projectile is given by the equation h=16t^2 + 368t where t is time, in seconds. the graph of the equation will be a parabola assume the volcano does not have a height. so, h= 0 and t=0 1.) when does the ash projectile reach it's maximum height? 2.)what is the maximum height? 3.)when does the ash projectile return to the ground?