Five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find their present ages

Given :

Find :

Solution :

Five years ago a man was seven times as old as his son.

Let us assume

son's age = (x - 5) years

man's age = (7x - 5) years

After five years

Son's age = (x + 5) years

Man's age = 3(x + 5) years

Now we will calculate son's present age

According to question

3(x + 5) = 7(x - 5) + 10

→ 3x + 15 = 7x - 35 + 10

→ 7x - 3x = -35 + 10 + 15

→ 4x = 40

→ x =

x = 10

Son's present age = 10 years

Calculating man's present age

Putting the value of x = 10 years

3(10 + 5) - 5

→ (30 + 15) - 5

→ 45 - 5

→ 40 years

Man's present age = 40 years

Final Answer :

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer