This figure is made up of a rectangle and parallelogram. what is the area of this figure? enter your answer in the box. do not round any side lengths. units² coordinate plane with axes labeled x and y. a closed figure is formed by a parallelogram and rectangle. the vertices are negative 7 comma 7, negative 3 comma 7, 6 comma 1, 4 comma negative 2, negative 5 comma 4, and negative 9 comma 4.

The first thing you should do in this case is to draw the vertices in the Cartesian plane and join each of the points.
 Then, to find the area of the figure you must first find the area of the rectangle and add it to the area of the parallelogram.
 Area of the rectangle:
 Ar = (w) * (l)
 Ar = (root ((6-4) ^ 2 + (1 - (- 2)) ^ 2)) * (root ((- 3-6) ^ 2 + (7-1) ^ 2))
 Ar = (3.61) * (10.82)
 Ar = 39
 Parallelogram Area: 
 Ap = b * h
 Ap = (root ((- 7 - (- 3)) ^ 2+ (7-7) ^ 2)) * (root ((- 7 - (- 7)) ^ 2+ (7-4) ^ 2) )
 Ap = (4) * (3)
 Ap = 12
 Total area:
  At = Ar + Ap = (39) + (12) = 51
 
 The area of the figure is:
  At = 51 Units ^ 2

The coordinates of point a right now is (-3,-1) you have to multiply these coordinates by a factor of 2 to get (-6,-2)