The sum of 4 consecutive numbers is 40. what is the second number in this sequence

Let us assume the first number = x
Then
The second number = x + 1
The third number = x +2
The fourth number = x + 3
Then we can write the equation as
x + x+ 1 + x + 2 + x+ 3 = 40
4x + 6 = 40
4x = 40 - 6
4x = 34
x = 34/4
   = 17/2
Then
The second number = x + 1
                                  = (17/2) + 1
                                 = (17 + 2)/2
                                 = 19/2
So the second consecutive number is 19/2

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