Given: δавс, m∠acb = 90° cd ⊥ ab, m∠acd = 60° bc = 6 cm find cd, area of δabc

1. If m∠ACB=90° and m∠ACD=60°, then m∠BCD=30°. Consider right triangle BCD. BC is its hypotenuse.

The leg that lies opposite to the 30° angle is half of hypotenuse, then BD=3 cm.

By the Pythagorean theorem,

2. Consider right triangle ACD, m∠ACD=60°, then m∠CAD=90°-60°=30°. Thus, the leg CD is opposite to the hypotenuse AC and

3. The area of ΔABC is

answer: .75 km

step-by-step explanation:

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )