Which point could be removed in order to make the relation a function? {(–9, –8), (–8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}

I believe that the correct answer would be (0,8)

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

c.)

step-by-step explanation: