Factor 2x2 + 7x + 3. (2x + 2)(x + 1) (2x + 3)(x + 1) (2x + 1)(x + 3)

(2x + 1)(x + 3)

It is probably easier to try the answer choices than to try to factor the expression yourself.

(2x + 2)(x + 1) = 2x² +4x +2

(2x + 3)(x + 1) = 2x² +5x +3

(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice

Constructed solution

If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.

... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7

Now, rewrite the x term using the sum of these numbers.

... 2x² +(1 +6)x +3

... 2x +x +6x +3 . . . . eliminate parentheses

... (2x +x) +(6x +3) . . . . group pairs of terms

... x(2x +1) +3(2x +1) . . . . factor each pair

... (x +3)(2x +1) . . . . . . matches the last selection

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

i think asking google will you get the answer to that question