Nala can spend no more than $150 per month on gasoline. she has already purchased $60 in gas this month. which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30? 30n + 60 > 150 30n + 60 < 150 60n + 30 < 150 60n + 30 > 150

tex]60+30n<150[/tex]

Step-by-step explanation:

Given :

Nala can spend no more than $150 per month on gasoline.

She has already purchased $60 in gas this month.

To Find:Which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30

Solution :

Since we are given that she already purchased for $60 in this month

Let now she will purchase n number of fill ups for the rest days of this month.

since cost of each fill up is $30

So, cost of n fill ups is 30 n

So, total she she spent this month = 60+30n

We are also given that she can spend no more than $150 per month.

So, inequality becomes:

Hence , inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30:

SO, option B is correct .

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

mark brainliest!

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"