Need asap 30 points

is △dbe similar to △abc ? if so, which postulate or theorem proves these two triangles are similar?

△dbe is similar to △abc by the sas similarity theorem .

△dbe is similar to △abc by the ssa similarity theorem .

△dbe is similar to △abc by the sss similarity theorem .

△dbe is not similar to △abc .

△DBE is similar to △ABC by the SAS Similarity Theorem .

Step-by-step explanation:

Given triangles in figure

we have to tell that is the triangles are similar or if similar then by which postulate.

In ΔDBE and ΔABC,

⇒

⇒

Hence, the sides of triangle are proportional.

And also ∠B=∠B (common) i.e the one angle congruent

Hence, △DBE is similar to △ABC by the SAS Similarity Theorem .

△DBE is similar to △ABC by the SAS Similarity Theorem .

Given triangles in figure

Step-By-Step Explanation:

we have to tell that is the triangles are similar or if similar then by which postulate.

In ΔDBE and ΔABC,

⇒

⇒

Hence, the sides of triangle are proportional.

And also ∠B=∠B (common) i.e the one angle congruent

Hence, △DBE is similar to △ABC by the SAS Similarity Theorem .

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

x=half

step-by-step explanation: