Challenging area question, pls list out all steps

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for these questions, i assumed the figure had some symmetric properties.

for the perimeter, see figure 1 attached.
perimeter is around 53.65 cm.



for the difference of the shaded area of a and the sum of the shaded areas of b and c, refer to figure 2 attached.

we first took one side of the square, rotated it until it touched the intersection as shown. this formed both a triangle and a sector of a circle.

we used formulas for those, and then, since it is symmetric (if you do the same thing, you'd get the same result), we found that 

   

then we determined new regions d and e so that we can use subtraction to determine the area of a.

   

the sum of the shades ares of b and c

   

difference between shaded area of a and b+c:

   

22.72 cm²

(i think actual answer without using 3.14 for pi is around 22.796 cm²)

yes

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!