Will give brainliest the displacement, x meters, from the origin at time, t seconds, of a particle moving in a straight line is given by x=t^3 -9t^2 +4 (i) find the particle's initial position. (ii) find an expression for the velocity as a function of time. (iii) find an expression for the acceleration as a function of time. (iv) at what times is the particle stationary? (v)at what time is the acceleration zero? find its velocity and position then

i) t=0, x = 4

ii) velocity = dx/dt = 3t^2 - 18t

iii) acceleration = d(velocity)/dt = 6t - 18

iv) vel=0 when particle is stationary, 3t^2 - 18t =0

t = 0 or 6

v) 6t - 18 = 0

t = 3

vel = 3(3^2) -18*3 = -27

position = 3^3 - 9*3^2 +4 = -50

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3