In the figure, if m∠abd = 120º, then m∠adc = º.

We must use the Law of Sines to solve this question, which is as follows:

a/sinA = b/sinB = c/sinC

This applies to any triangle. We are told that ∠ABD = 120º. We are asked to solve for ∠ADC. We know that ∠ADC + ∠ADB = 180º. If we assign ∠ADC = x, then ∠ADB = 180º - x. We can now apply the law of sines to this data.

35/sin120 = 30/sin(180-x)

sin(180-x) = (30/35)(sin120)

sin(180-x) = 0.742

sin-1(sin(180-x)) = sin-1(0.742)

180 - x = 48º

x = 132º

We have already assigned x = ∠ADC; therefore, ∠ADC = 132º.

Step-by-step explanation:

i need the table so i can see

step-by-step explanation: