If a chessboard (8x8) were to have pennies placed on each square such that 1 penny was placed on the first square, 2 on the second, 4 on the third, and so on (doubling the number of pennies on each subsequent square), how many pennies would be on the chessboard when finished?

64 according to e2020

18446,74,40,73.70,95,51,615

Step-by-step explanation:

There are in total 64 squares on a chess board.

I penny placed on I square, II on 2nd square, 4 on 3rd and so on.

The no of pennies on each square form a geometric sequence with each term multiplied by 2 by the previous term

Thus no of pennies placed would be

1,2,4,.....

The total no of pennies placed = sum of a geometric series with I term 1 and common ratio 2

=

=18446,74,40,73.70,95,51,615

is there answer choices?

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer