Points p(6, 0, 4), q(3, 2, 1), and r are collinear such that pq=qr. what are the coordinates of point r? a. (0, 4, -2) b. (-3, 2, -3) c. (1, -2, 0) d. (4, 1, -3)

If PQ = QR, then the difference of each of the x-, y-, and z-coordinates between PQ and between QR would be identical.
P - Q: x = 6 - 3 = 3, y = 0 - 2 = -2, z = 4 - 1 = 3
Subtract these differences from Q again to get the coordinates for R:
Rx = 3 - 3 = 0
Ry = 2 - (-2) = 4
Rz = 1 - 3 = -2
So the coordinates of R are (0, 4, -2), which is Choice A.

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