3(4x+3)+4(6x+1)=43 how do i solve it

Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
-3 (4 x + 3) = -12 x - 9:
-12 x - 9 + 4 (6 x + 1) = 43
4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
(24 x - 12 x) + (4 - 9) = 43
24 x - 12 x = 12 x:
12 x + (4 - 9) = 43
4 - 9 = -5:
12 x + -5 = 43
Add 5 to both sides:
12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
12 x = 43 + 5
43 + 5 = 48:
12 x = 48
Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
12/12 = 1:
x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
  x = 4