Calculate dy/dx when y^2 = (3x + 1)^3 / 9x + 2

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 y^2 = (3x + 1)^3 / 9x + 2
2*y*(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ ((9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ (2*y*(9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(6x + 1))/ (2*y*(9x + 2)^2)
 answer 
 A

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