An archery target consists of a circular bull's-eye with radius x, surrounded by four rings with width y. what is the area of the outermost ring in terms of x and y?

given:
   bull's eye radius= x
 width of surrounding rings=y

   solution:
   Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring =Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
 =Ď€(2xy+7y^2)
 hence the area of the outermost ring in terms of x and y is Ď€(2xy+7y^2).

It is the top one. the answer is -7. that is smallest