Find an equation of the line that satisfies the given conditions. through (−5, −7); perpendicular to the line passing through (−2, 5) and (2, 3)

The equation would be y = 2x + 3

Step-by-step explanation:

In order to solve this, we first need to find the slope of the line between (-2, 5) and (2, 3). In order to do this, we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - 5)/(2 - -2)

m = -2/4

m = -1/2

Now that we have the original line with a slope of -1/2, we can tell a perpendicular line would have a slope of 2. This is because perpendicular lines have opposite and reciprocal slopes. Now we can use that slope and the given point in point-slope form to get the answer. Be sure to solve for y.

y - y1 = m(x - x1)

y + 7 = 2(x + 5)

y + 7 = 2x + 10

y = 2x + 3

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: