This year the hawks won 20 games. last year the hawks won 16 games. what is the percent increase in the number of games the hawks won from last year to this year?

% increase = 25%

Step-by-step explanation:

Number of games won this year; N1 = 20 games

Number of games won last year; N2 = 16 games

To calculate the percentage increase, we will use the formula;

% increase = (increase in number of games won/original number of games won) x 100%

Now, increase in number of games won = N1 - N2 = 20 - 16 = 4

Since original number of games won is 16,thus;

% increase = 4/16 x 100% = 25%

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3