The rectangle shown has a perimeter of 34 cm and the area given its length is 5 more than twice the width write and solve a system of equations to find the dimensions of the rectangle a=52cm^2

The width and the length of rectangle are 4 cm and 13 cm respectively .

Step-by-step explanation:

Let the width be x

We are given that its length is 5 more than twice the width

So, length= 2x+5

Perimeter of rectangle =

                                    =  

We are given that perimeter is 34 cm

So,  

x=4

So, width = 4 cm

Length = 2x+5=2(4)+5=13 cm

Area of rectangle =

We are given that area is 52sq.cm

So,

Since width cannot be negative

So,width = 4 cm

Length = 2x+5=2(4)+5=13 cm

Hence The width and the length of rectangle are 4 cm and 13 cm respectively .

i belive those are the ones that are under 90 degreese.

27 +27 or 27times 2=54

the diffrence is 0