Find the illegal values of b in the fraction 2b ^2 + 3b − 10 b ^2 − 2b − 8 . a. b = −5 and 2 b. b = −2 and −4 c. b = −5, −2, 2, and 4 d. b = −2 and 4

1) It seems that the fraction is:

2b^2 + 3b  - 10

    b^2 - 2b - 8

2) Given that the division by 0 is not defined, the illegal values of b are those that make b^2 - 2 b - 8 = 0

3) Solve b^2 - 2b - 8 = 0

You can factor: b^2 - 2b - 8 = (b - 4 ) (b + 2)

=> b = 4 and b =- 2

4) option D. b = - 2 and 4.

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