There were a total of 125 cars at a car dealership. a salesperson sold 68 of the cars in one month. write and solve an inequality that describes how many more cars, at most, the salesman left to sell

Let c represent the number of cars that the salesman has left to sell.

      68 + c ≤ 125
68-68 + c ≤ 125 -68
               c≤57
The solution is c ≤ 57. The salesman has at most 57 cars left to sell

68 + c ≤ 125; c ≤ 57 cars or less left to sell.

The answer is 10. and if you go by pemdas you would 1. multiplication 2. division 3. addition 4. subtraction