Graph the system of equations on your graph paper to answer the question. {y=x+2 y=−x+8 what is the solution for this system of equations? enter your answer in the boxes. ( , )

The slope intercept form of a line is y = mx +b.

Where m= slope and b= y-intercept.

Let's compare the first equation with this equation to get the value of m and b.

After comparing the first equation y = 1x + 2 with y = mx + b we will get m =1 and b=2.

Next step is to plot y-intercept = 2 on the graph.

Now slope =

We can represent slope =1 as .

Hence, .

By comparing numerator and denominator we will get,

Rise = 1 and run = 1.

Rise= 1 means go 1 unit up and for run =1 1 unit to the right. Thefore go 1 unit up and then 1 unit to the right from the y-intercept = 2. So, it would be (1, 3). Now keep repating this method to get as many point as you want then connect all the points to get the graph of the first equation.

By using the same method we will find the slope ad y-intercept of the second line. So,

m = -1 and b = 8.

Now plot y-intercept = 8.

m = -1 can be represent as -1/1.

So, rise= -1 and run =1.

Now go 1 unit down and 1 unit to the right.

Now point of intersection of these two lines will give the solution which is (3, 5).

So, the solution of the given system is (3, 5)

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what is the image?

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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