Shureka washburn has scores of 89 , 65, 68, and 88 on her algebra tests. a. use an inequality to find the scores she must make on the final exam to pass the course with an average of 78 or higher, given that the final exam counts as two tests. b. explain the meaning of the answer to part (a).

79. Set up an equation to solve this problem. Suppose she needs at least a score of x points. Her current total scores is 89+65+68+88=310. Her total score will be 310+2x (since final exams counts as two tests). The average score is total points divided by number of tests, and it has be bigger or equal to 78, so (310+2x)/6>=78. We solve it and get x=79. She has to score at least 79 on her final exam in order to jhave an overall average of 78.

You have 2 sides that are 2 cms and you have 6 sides that are 1/2 cm and you have 4 sides that are 1 cm. the smallest sides are 1/2 the medium sized sides are 1 and the smallest are 1/2. so to find the perimeter you have to add them all up together so your answer will be 11 cm's