Equation for a circle with a diameter that has endpoints at (2, –5) and (8, –9)

The standard form for the equation of a circle is :

 So the midpoint of the diameter with endpoints at (2,-5)and(8,-9) is :

 ((2+(8))/2,(-5+(-9))/2)=(5,-7)

 So the point (5,-7) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(2−(5))^2+(-5−(-7))^2=9+4=13

 ⇒r=√13

 Subtituting h=5, k=-7 and r=√13 into EQ(1) gives :

 (x-5)^2+(y+7)^2=13

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.