Acity's population is represented by the function p=25,000(1.0095)t p=25,000(1.0095)t , where t is time in years. how could the function be rewritten to identify the daily growth rate of the population? what is the approximate daily growth rate? function p= 25,000 (1.00095 ^1/365t) ^365t functions: p = 25,000 (1.0095 ^1/365) ^365t p = 25,000 (1 + 0.0095) ^t/365 p = 25,000 (1 + 0.0095 ^1/365) ^365t daily growth rates: 0.003% 0.95% 0.0012%

To convert the function representing the yearly growth of population , to the function representing the daily growth of population we divide the rate of increase by 365 , as there are 365 days in a year.

Now the given function is

which can be written as

It means the yearly rate of increase is 0.0095, we divide it by 365

So

The daily growth is given by

And the approximate daily growth rate is

= 0.003%

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

46.2+112.3

step-by-step explanation: