Three times the lesser of two consecutive even integers is 6 less than six times the greater number. find the integer

The required integer is - 2

We could express the two consecutive even ntegers as :

n and n+2

Lesser integer = n

greater integer = n + 2

Three times the lesser = 3n

Six times the greater = 6(n+2)= 6n + 12

3n = (6n + 12) - 6

3n = 6n + 12 - 6

3n = 6n + 6

3n - 6n = 6

-3n = 6

n = 6/-3

n = - 2

The integer is - 2

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x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

answer: i believe the answer is e

step-by-step explanation: