Arectangular banner is 5 inches longer than its width. a triangular poster is 3 times as long as its height. both the poster and the banner has an area of 24 square inches. part a: what is the height and base of the poster? justify your answer. part b: what is the length and width of the banner? justify your answer.

Part A

For the triangle

A=(B*h)/2   A=24

B=3*h

3*h^2=48   h^2=16  h=4      B=3*4  B=12

 the height and base of the poster are h=4 and B=12 respectively

 Part B

For the rectangle

Area A=L*W

Only positive W values make sense here

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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a - base

b - exponent

so,