What is the range of f(x)=2x squared-2x+5 if the domain is (-2, -1, 0, 1, 2)?

Plug in the 5 values in the domain 

f(-2) = 2(-2)^2 - 2(-2) + 5 =  8+4+5 = 17   so first number in the range is 17.
f(-1) = 2(-1)^2 -2(-1) + 5 =  2 + 2 + 5 = 9 
f(0)  = 0 - 2 + 5 = 5
fond f(1) and f(2) in the same way 

results are 17,9,5,5,9

so the range is {5, 9,17}    (you don't repeat values)

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